Secantes



Y + 10
2x = 3x -20 3(20) – 20
= y + 10 = 40
20 = 3x -2x 60 – 20 = 40 y = 40 -10
20 =x y = 30
20 = 3x -2x 60 – 20 = 40 y = 40 -10
20 =x y = 30
![]() |

4y

X + 2y = 92 92 + 4y = 180
x + 2(22) = 92 4y = 180 - 92
x + 44 = 92 4y = 88
x = 92 – 44 y =
x = 48 y = 22
x + 2(22) = 92 4y = 180 - 92
x + 44 = 92 4y = 88
x = 92 – 44 y =

x = 48 y = 22


70° 57°



9x – 2y = 57 45 + 2y = 57
16 – 10y = -140 2y = 57 - 45
45 + 10y = 289 2y = 12
9x = 145 y =

x =

X = 5
Teoremas

2y
90° x 2x + x = 90
3x = 90
x =
x = 30
3x = 90
x =

x = 30


90° x
x + x = 90 4x = (90) (3) 
x +
= 90 4x = 270 = 22.5
x =
90 x =
x = 67.5






x = 67.5

B A = 61.2 A + A + 18 +
= 180

A C B = 79.2 2A +
18 +
+
= 180


C =
39.6
2A +
+
9 = 180 - 18

2A +
= 180 – 18 - 9

2A +
= 153
+
=
= 153
= 153
5A = (153) (2)
5A = 306
A =
A = 61.2





5A = (153) (2)
5A = 306
A =

A = 61.2






x= X = 50 Y = 95
Y = 130

y = X = 45°
Teorema de Pitágoras
A =
3 B = 4 C = 5
(3)² (4)² 9 + 16
9 16 25 =
=
5
(3)² (4)² 9 + 16
9 16 25 =

A =
15 B = 8 C = 17
(15)² 225 - 289 (17)²
225 64 =
=
8 289
(15)² 225 - 289 (17)²
225 64 =



.-Calcular la altura de un triangulo equilátero que mide 10 metros por lado
C = A = 25
B = B = 8 .6
C = 100
B = B = 8 .6
C = 100


10 A= 5


B = (5)² = 25 A = 25 25 + 25 = 50
C = B = 25

C = 7 .07
A = 5
(5)² = 25


.-Calcular el área de un hexágono, si su apotema es 8.66 y cada uno de sus lados 12
12 12



8.66


1200m²




8






65 32 28
x =65° 32’’ 28’ 89 59 60
24° 27’ 32’’
y = 24° 27’’ 32’



y = 123° 32’’ 26 179 59 60
56° 27’’ 34’
x =

Grados y Radianes
223° = (223) (0.017453) = 3.89 rad.
58° 39’’ 48’ = 1.02 rad
= .8
39 + .8 = 39.8
= .66
58 + .66 = 58.66
58.66 (0.017453) = 1.02
58° 39’’ 48’ = 1.02 rad

39 + .8 = 39.8

58 + .66 = 58.66
58.66 (0.017453) = 1.02